这样能过?
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这样能过?
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magic_apple楼主2024/9/19 19:23
#include <bits/stdc++.h>
using namespace std;
#define int long long
int a[1000010],b[1000010];
signed main(){
    ios::sync_with_stdio(false);
    cin.tie(0),cout.tie(0);
    int n;cin>>n;
    int ans2=0,mn=0x3f3f3f3f;
    for (int i=1;i<=n;i++) cin>>a[i];
    for (int i=1;i<=n;i++) cin>>b[i],ans2+=b[i],mn=min(mn,max(0ll,a[i]-b[i]));
    ans2+=mn;
    int ans1=0;
    for (int i=2;i<=n;i++){
        int s,w;cin>>s>>w;
        ans1+=w*2;
    }
    cout<<ans1<<' '<<ans2<<endl;
    return 0;
}
2024/9/19 19:23
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