连续读入 $n$ 个数字，分别用三种读入：

1. ios::sync_with_stdio(0) + cin.tie + cin>>var
2. scanf("%d",&var)
3. 快读

namespace IO
{
    char ibuf[(1 << 20) + 1], *iS, *iT;
#if ONLINE_JUDGE
#define gh() (iS == iT ? iT = (iS = ibuf) + fread(ibuf, 1, (1 << 20) + 1, stdin), (iS == iT ? EOF : *iS++) : *iS++)
#else
#define gh() getchar()
#endif
    inline long long read()
    {
        char ch = gh();
        long long x = 0;
        bool t = 0;
        while (ch < '0' || ch > '9')
            t |= ch == '-', ch = gh();
        while (ch >= '0' && ch <= '9')
            x = x * 10 + (ch ^ 48), ch = gh();
        return t ? -x : x;
    }
    inline char getc()
    {
        char ch = gh();
        while (ch < 'a' || ch > 'z')
            ch = gh();
        return ch;
    }
}
using IO::getc;
using IO::read;

然后 var=read()

此时这些读入方式的速度 $n$ 的取值分别在哪些范围会最快？