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pw384楼主2013/11/4 20:27

Let N be a positive integer and let N be split into k equal parts, r = N/k, so that N = r + r + ... + r.

Let P be the product of these parts, P = r ×r × ... × r = rk.

将正整数N分为k个相等的部分r,有r=N/k

另P=r×r×...×r=rk

For example, if 11 is split into five equal parts, 11 = 2.2 + 2.2 + 2.2 + 2.2 + 2.2, then P = 2.2^5 = 51.53632.

例如,将11分为五等份 则P=2.2^5

Let M(N) = Pmax for a given value of N.

另M(N)为满足要求的对应N的最大的P

It turns out that the maximum for N = 11 is found by splitting eleven into four equal parts which leads to Pmax = (11/4)^4; that is, M(11) = 14641/256 = 57.19140625, which is a terminating decimal.

容易知道,N=11时,Pmax=57.19140625,是有穷小数

However, for N = 8 the maximum is achieved by splitting it into three equal parts, so M(8) = 512/27, which is a non-terminating decimal.

而N=8时,Pmax=512/27,是无尽小数

Let D(N) = N if M(N) is a non-terminating decimal and D(N) = -N if M(N) is a terminating decimal.

设D(n)=n(若M(n)无尽),D(n)=-n(若M(n)有尽)

2013/11/4 20:27
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