套用的高精度模板,可是为啥会超时呢。。难道是memset的原因吗?
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套用的高精度模板,可是为啥会超时呢。。难道是memset的原因吗?
479181
duheru666楼主2022/11/24 12:56
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <cstdlib>
#include <cmath>
#include <stack>
#include <queue>
#include <vector>
#include <map>
#include <set>
#include<bitset>
#include<list> 
#include <algorithm>
#include <cassert>
#define pii pair<LL,LL>
#define se second
#define fi first
#define rep(i,a,b) for (LL i=a;i<b;++i)
#define per(i,a,b) for (LL i=a;i>b;--i)
#define mid ((l+r)/2)
#define lson(root) ((root)<<1)
#define rson(root) (((root)<<1)|1)
#define MEM(a,x) memset(a,x,sizeof(a))
#define M(x) ((x)%MOD)
#define endl '\n'   
typedef long long LL;
typedef unsigned long long ULL;
using namespace std;
const LL INF=0x3f3f3f3f;
const LL MOD=1e9+7;
const int N=1e3+7;
const int M=5e4+7;
 
struct BigInteger {
    typedef unsigned long long LL;
 
    static const int BASE = 100000000;
    static const int WIDTH = 8;
    vector<int> s;
 
    BigInteger& clean(){while(!s.back()&&s.size()>1)s.pop_back(); return *this;}
    BigInteger(LL num = 0) {*this = num;}
    BigInteger(string s) {*this = s;}
    BigInteger& operator = (long long num) {
        s.clear();
        do {
            s.push_back(num % BASE);
            num /= BASE;
        } while (num > 0);
        return *this;
    }
    BigInteger& operator = (const string& str) {
        s.clear();
        int x, len = (str.length() - 1) / WIDTH + 1;
        for (int i = 0; i < len; i++) {
            int end = str.length() - i*WIDTH;
            int start = max(0, end - WIDTH);
            sscanf(str.substr(start,end-start).c_str(), "%d", &x);
            s.push_back(x);
        }
        return (*this).clean();
    }
 
    BigInteger operator + (const BigInteger& b) const {
        BigInteger c; c.s.clear();
        for (int i = 0, g = 0; ; i++) {
            if (g == 0 && i >= s.size() && i >= b.s.size()) break;
            int x = g;
            if (i < s.size()) x += s[i];
            if (i < b.s.size()) x += b.s[i];
            c.s.push_back(x % BASE);
            g = x / BASE;
        }
        return c;
    }
    BigInteger operator - (const BigInteger& b) const {
        assert(b <= *this); // 减数不能大于被减数
        BigInteger c; c.s.clear();
        for (int i = 0, g = 0; ; i++) {
            if (g == 0 && i >= s.size() && i >= b.s.size()) break;
            int x = s[i] + g;
            if (i < b.s.size()) x -= b.s[i];
            if (x < 0) {g = -1; x += BASE;} else g = 0;
            c.s.push_back(x);
        }
        return c.clean();
    }
    BigInteger operator * (const BigInteger& b) const {
        int i, j; LL g;
        vector<LL> v(s.size()+b.s.size(), 0);
        BigInteger c; c.s.clear();
        for(i=0;i<s.size();i++) for(j=0;j<b.s.size();j++) v[i+j]+=LL(s[i])*b.s[j];
        for (i = 0, g = 0; ; i++) {
            if (g ==0 && i >= v.size()) break;
            LL x = v[i] + g;
            c.s.push_back(x % BASE);
            g = x / BASE;
        }
        return c.clean();
    }
    BigInteger operator / (const BigInteger& b) const {
        assert(b > 0);  // 除数必须大于0
        BigInteger c = *this;       // 商:主要是让c.s和(*this).s的vector一样大
        BigInteger m;               // 余数:初始化为0
        for (int i = s.size()-1; i >= 0; i--) {
            m = m*BASE + s[i];
            c.s[i] = bsearch(b, m);
			m -= b*c.s[i];
        }
        return c.clean();
    }
    BigInteger operator % (const BigInteger& b) const { //方法与除法相同
        BigInteger c = *this;
        BigInteger m;
        for (int i = s.size()-1; i >= 0; i--) {
            m = m*BASE + s[i];
            c.s[i] = bsearch(b, m);
            m -= b*c.s[i];
        }
        return m;
    }
    // 二分法找出满足bx<=m的最大的x
    int bsearch(const BigInteger& b, const BigInteger& m) const{
        int L = 0, R = BASE-1, x;
        while (1) {
            x = (L+R)>>1;
            if (b*x<=m) {if (b*(x+1)>m) return x; else L = x;}
            else R = x;
        }
    }
    BigInteger& operator += (const BigInteger& b) {*this = *this + b; return *this;}
    BigInteger& operator -= (const BigInteger& b) {*this = *this - b; return *this;}
    BigInteger& operator *= (const BigInteger& b) {*this = *this * b; return *this;}
    BigInteger& operator /= (const BigInteger& b) {*this = *this / b; return *this;}
    BigInteger& operator %= (const BigInteger& b) {*this = *this % b; return *this;}
 
    bool operator < (const BigInteger& b) const {
        if (s.size() != b.s.size()) return s.size() < b.s.size();
        for (int i = s.size()-1; i >= 0; i--)
            if (s[i] != b.s[i]) return s[i] < b.s[i];
        return false;
    }
    bool operator >(const BigInteger& b) const{return b < *this;}
    bool operator<=(const BigInteger& b) const{return !(b < *this);}
    bool operator>=(const BigInteger& b) const{return !(*this < b);}
    bool operator!=(const BigInteger& b) const{return b < *this || *this < b;}
    bool operator==(const BigInteger& b) const{return !(b < *this) && !(b > *this);}
};
 
ostream& operator << (ostream& out, const BigInteger& x) {
    out << x.s.back();
    for (int i = x.s.size()-2; i >= 0; i--) {
        char buf[20];
        sprintf(buf, "%08d", x.s[i]);
        for (int j = 0; j < strlen(buf); j++) out << buf[j];
    }
    return out;
}
 
istream& operator >> (istream& in, BigInteger& x) {
    string s;
    if (!(in >> s)) return in;
    x = s;
    return in;
}

typedef BigInteger bigint;

struct tmp{
    bigint a,b;
}xxx[N];

int cmp(tmp& x,tmp& y){
    return x.a * x.b < y.a * y.b;
}

int n;
bigint x,y;
bigint ans;

void solve(){
    cin>>n;
    
    cin>>x>>y;

    rep(i,1,n+1){
        cin>>xxx[i].a>>xxx[i].b;
    }
    sort(xxx+1,xxx+n+1,cmp);

    
    ans=x/xxx[1].b;
    rep(i,2,n+1){
        x=x*xxx[i-1].a;
        if (ans<x/xxx[i].b) ans=x/xxx[i].b;
    }
    cout<<ans;
    // rep(i,1,n+1){
    //     cout<<xxx[i].a<<' '<<xxx[i].b<<endl;
    // }
    return ;
}

int main(){
    #ifndef ONLINE_JUDGE
        freopen("title.in","r",stdin);
        freopen("title.out","w",stdout);
    #endif
    // ios::sync_with_stdio(false);
    // cin.tie(0);cout.tie(0);
    int _=1;
    // cin>>_;
    // scanf("%d",&_);
    while (_--) solve();
    // rep(i,1,_+1){
    //  cout<<"Case "<<i<<": ";
    //  solve();
    // }
    return 0;
}
2022/11/24 12:56
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