于是我就这么被嫌弃了QAQ
@学委 从我的模板里截的片段...
template<> inline double read()
{
register double aa, bb;
register char ch;
register char *S = io::S, *T = io::T;
while (ch = getc(), (ch<'0' || ch>'9'))
; aa = ch - '0';
while (ch = getc(), (ch >= '0'&&ch <= '9'))
aa = aa * 10 + ch - '0';
if (ch == '.') {
bb = 1;
while (ch = getc(), ch >= '0'&&ch <= '9')
bb *= 0.1, aa += bb*(ch - '0');
}
io::S = S, io::T = T;
return aa;
}
double(*readf)() = read<double>;
实测还是挺快的QAQ
@rswork https://rsworktech.blog.luogu.org/powershell-math
感谢投稿,过于简略看不出有什么用
@mimi https://www.luogu.org/blog/[mimi](/space/show?uid=36532)/ci-fen-gou-shu-jie-shao-zong-jie-yu-li-ti
感谢投稿,原理解释不够
@shadowice1984 怎么我看不见
@JRX2015U43 https://jrx.blog.luogu.org/te-zheng-fang-cheng
感谢投稿,推导过程希望简化(当然你会生成函数的话这些东西都不用证
@zybnxy https://www.luogu.org/blog/51645/shuo-lun-zhi-shuo-ji-ji-shai-fa
感谢投稿,已加入候选队列
标题改为质数判定方法,O(sqrt(N)/3)处可以预处理<=sqrt(N)的素数达到更快
@ComeIntoPower 2018-10-29 08:00 @shadowice1984 怎么我看不见
从现在开始,管理会消失到11-1