n/2+n/3+n/5+n/7+n/11+⋯n/2+n/3+n/5+n/7+n/11+\cdotsn/2+n/3+n/5+n/7+n/11+⋯
即 ∑p∈primen/p\sum_{p\in prime}n/p∑p∈primen/p
为何趋近于 nloglognn\log\log nnloglogn。