@joebiden 我稍微改了该你的程序 (捞贴)

#include<bits/stdc++.h>
using namespace std;

int j, numn = 108, numv = 108, numadj = 108, numadv = 108, numl = 4, numcon = 38, numfam = 160;

string nouns[200] = {"小明" , "太阳" , "花儿" , "世界" , "草地" , "奋斗者们" , "队列" , "空地" , "机会" , "方向" , "沙土" , "居民" , "牧童" , "毛巾" , "活口" , "男女" , "大衣" , "布衣" , "青菜" , "砍刀" , "厂房" , "工厂" , "冷风" , "口水" , "大爷" , "星空" , "田园" , "轿车" , "开头" , "师父" , "意思" , "公路" , "金子" , "处方" , "别处" , "对手" , "页码" , "乡亲" , "丁香" , "抹布" , "沙锅" , "云彩" , "分秒" , "总理" , "大门" , "围巾" , "花草" , "苦水" , "男生" , "茶叶" , "京城" , "家乡" , "恩师" , "动作" , "两旁" , "大豆" , "往日" , "主意" , "干花" , "笑话" , "个子" , "光亮" , "生人" , "日夜" , "时间" , "大小" , "一向" , "前天" , "孩子" , "小米" , "来人" , "奶妈" , "烟雾" , "远近" , "难题" , "布告" , "所有" , "干红" , "见识" , "年岁" , "海马" , "家门" , "西方" , "中午" , "黄豆" , "睡衣" , "花车" , "电话" , "影响" , "对面" , "画像" , "长话" , "正午" , "少爷" , "题目" , "本土" , "大队" , "说明" , "外语" , "梅子" , "男声" , "可乐" , "往事" , "太阳" , "日照" , "午时" , "师母" , "半边"};
string verbs[200] = {"绽放" , "成长" , "毁灭" , "沉睡" , "哭泣" , "突破" , "上班" , "开春" , "手写" , "播种" , "报到" , "发烧" , "放手" , "出活" , "把门" , "提早" , "对不起" , "不在" , "道破" , "开头" , "消灭" , "意思" , "点明" , "处方" , "自学" , "相连" , "追赶" , "诉说" , "堆积" , "立正" , "张望" , "跟着" , "总理" , "收听" , "改动" , "放松" , "取暖" , "对答" , "吹牛" , "动作" , "笑话" , "满足" , "代替" , "生人" , "安心" , "得力" , "念旧" , "回忆" , "多嘴" , "告吹" , "布告" , "所有" , "闭气" , "公开" , "见识" , "开业" , "影响" , "吃苦" , "值日" , "画像" , "夸奖" , "挂念" , "说明" , "灭火" , "怕人" , "叫唤" , "听讲" , "带头" , "就学" , "把握" , "用功" , "生长" , "退休" , "进出" , "舍身" , "发展" , "踏青" , "到达" , "干杯" , "借助" , "过关" , "进取" , "吹捧" , "过门" , "明白" , "发言" , "热爱" , "搭话" , "冷冻" , "捉拿" , "缩短" , "没完" , "总计" , "把守" , "入睡" , "躲让" , "漂流" , "过去" , "过冬" , "从军" , "变化" , "改正" , "开工" , "出走" , "自许" , "送行" , "对话" , "看病"};
string adj[200] = {"昔日" , "未来" , "美丽" , "痛苦" , "新生" , "富有革命精神" , "友爱" , "清白" , "出活" , "次要" , "齐心" , "高深" , "鲜美" , "光亮" , "安心" , "得力" , "所有" , "公开" , "影响" , "大忙" , "刻苦" , "怕人" , "火热" , "合法" , "洁净" , "完美" , "冰冷" , "用功" , "友好" , "刚好" , "可心" , "重要" , "草绿" , "详细" , "正好" , "老大" , "明白" , "潮湿" , "低级" , "着急" , "秀美" , "进步" , "完整" , "不行" , "细小" , "不合" , "黄花" , "美好" , "不定" , "高远" , "业余" , "直接" , "听说" , "聪明" , "齐全" , "亲爱" , "和气" , "迷你" , "正常" , "弯曲" , "公办" , "乐观" , "清新" , "深情" , "非分" , "秀丽" , "知己" , "精彩" , "亮闪闪" , "可笑" , "大量" , "相同" , "有力" , "暗淡" , "原来" , "不快" , "本来" , "发火" , "主要" , "天生" , "专业" , "真实" , "暖和" , "鲜艳" , "礼貌" , "芳香" , "平常" , "野生" , "拥挤" , "高级" , "共同" , "冷清" , "广大" , "黄色" , "自然" , "听话" , "永久" , "朝阳" , "草本" , "平淡" , "纯净" , "平安" , "无知" , "日常" , "凉快" , "中用" , "细心" , "要紧"};
string adv[200] = {"迅速","快乐","愤怒","慌张","自信","勇敢","跟着","大小","一向","对面","有时","刚好","跟手","正好","常常","老大","只好","左右","多少","赶早","莫非","多方","向来","不定","再次","就是","到底","多么","常年","各个","一同","处处","原来","本来","多半","随后","大多","时常","只是","分别","高低","最好","另外","来回","共同","说话","不要","死活","永远","自然","回头","可是","从来","苦口","大力","先后","接连","赶忙","要紧","更加","当真","好像","完全","亲自","一定","真正","到处","急忙","照样","一直","全都","长短","刚刚","早晚","不用","千万","一起","从此","格外","一共","总共","已经","根本","再三","赶快","正在","一会儿","亲手","非常","经常","连忙","也许","总算","及时","实在","迟早","始终","其实","不必","相互","碰巧","重新","沿路","绝对","首先","历来","互相","未免"};
string like[200] = {"如","像", "仿佛", "就似"};
string connect[200] = {"着","了","过"};
string ques[200] = {"为什么","如何让","何时能有"};
string gt[200] = {"多么","好一个","真是"};
string gtback[200] = {"啊","哇","呀","哟"};
string obq[200] = {"难道","怎能","怎么","何"};
string obend[200] = {"吗","呢"};
string con_j[200] = {"无论如何","既然如此","根据上述的话","如此这般","总的来说","并且","一个令人难以置信的事实是","因此","因为","但是","哪怕","然后","就是","那么","原来","只是","要么","另外","自然","可是","比方","只要","只有","如果","万一","要是","为了","由于","而且","除非","接着","尔后","首先","并且","于是","不但","还是","然而"};
string famous[200] = {	"爱迪生曾经说过:成功来自1%的灵感和99%的努力.",
						"金山银山不如绿水青山,",
						"失败是成功之母,",
                      	"马克思在《资本论》中提到:有10%的利润,资本就会活跃起来,.....有100%的利润,资本就敢践踏人间法律,有300%的利润,资本会不顾被绞死的风险.",
                      	"哥白尼说,人的天职在勇于探索真理.",
                      	"雷锋曾在日记中提到,人的生命是有限的，可是，为人民服务是无限的，我要把有限的生命，投入到无限的为人民服务之中去。" ,
                      	"雨果认为,人的智慧掌握着三把钥匙，一把开启数字，一把开启字母，一把开启音符。知识、思想、幻想就在其中。",
                      	"爱因斯坦说,人只有献身于社会，才能找出那短暂而有风险的生命的意义。" ,
                      	"鲁迅讲到, 希望是附丽于存在的，有存在，便有希望，有希望，便是光明。" ,
                      	"莎士比亚说, 抛弃时间的人，时间也抛弃他。",
                      	"马克吐温曾说过,黄金时代在我们面前而不在我们背后。","理想的书籍是智慧的钥匙。","没有智慧的头脑，就象没有腊烛的灯笼。 ","读书给人以快乐、给人以光彩、给人以才干。","读一本好书，就如同和一个高尚的人在交谈。","你热爱生命吗？那么别浪费时间，因为时间是组成生命的材料。 ","书籍是造就灵魂的工具。","天才免不了有障碍，因为障碍会创造天才。","书籍是全世界的营养品，生活里没有书籍就好像没有阳光；智慧里没有书籍就好像鸟儿没有翅膀。","今天应做的事没有做，明天再早也是耽误了。","没有一种不幸可与失掉时间相比了。","成功＝艰苦的劳动＋正确的方法＋少谈空话。","无知是迷信之母。","物竞天择，适者生存。","读一切好书，就是和许多高尚的人谈话。","最聪明的人是最不愿浪费时间的人。","完成工作的方法，是爱惜每一分钟。","理想的书籍是智慧的铜匙。","读书而不思考，等于吃饭而不消化。","人的影响短暂而微弱，书的影响则广泛而深远。","奇迹多在厄运中出现。","对自己不满是任何真正有才能的人的根本特征之一。","金钱这种东西，只要能解决个人的生活就行，若是过多了，它会成为遏制人类才能的祸害。 ","没有大胆的猜测就作不出伟大的发现。 ","先相信你自己，然后别人才会相信你。","耐心是一切聪明才智的基础。","合理安排时间，就等于节约时间。","浪费时间是一桩大罪过。","我扑在书上，就像饥饿的人扑在面包上。","不要问你的国家能够为你做些什么，而要问你可以为国家做些什么。","有很多良友，胜于有很多财富。","世界上最宽阔的是海洋，比海洋更宽阔的是天空，比天空更宽阔的是人的胸怀。","衡量一个人的真正品格，是看他在知道没人看见的时候干些什么。","读一本好书，就是和许多高尚的人谈话。","希望是生命的源泉，失去它生命就会枯竭。","如果说我比别人看得要远一点，那是因为我站在巨人的肩上。","我的最高原则是：不论对任何困难都绝不屈服。","青年时种下什么，老年时就收获什么。","对一切来说，只有热爱才是最好的老师，它远远胜过责任感。","生活就像海洋，只有意志坚强的人，才能到达彼岸。 ","没有伟大的愿望，就没有伟大的天才。","读一切好的书，就是和许多高尚的人说话。","不经巨大的困难，不会有伟大的事业。","一切节省，归根到底都归结为时间的节省。","今天所做之事勿候明天，自己所做之事勿候他人。 ","坚强的信心，能使平凡的人做出惊人的事业。","我所学到的任何有价值的知识都是由自学中得来的。","天才就是百分之二的灵感，百分之九十八的汗水。","人并不是因为美丽才可爱，而是因为可爱才美丽。 ","理想的书籍是智慧的钥匙。","立志、工作、成功，是人类活动的三大要素。","灵感--这是一个不喜欢采访懒汉的客人。","天才出于勤奋。","人的差异在于业余时间。","人不是为失败而生的，一个人可以被消灭，但不能被打败。","机遇只偏爱那些有准备的头脑。","人的一生可能燃烧也可能腐朽，我不能腐朽，我愿意燃烧起来！ ","失败乃成功之母。 ","人只有献身于社会，才能找出那短暂而有风险的生命的意义。","学习永远不晚。","辛苦是获得一切的定律。","利用时间是一个极其高级的规律。","天才就是这样，终身努力，便成天才。","不知道并不可怕和有害。任何人都不可能什么都知道，可怕的和有害的是不知道而伪装知道。","浪费别人的时间是谋财害命，浪费自己的时间是慢性自杀。","忘掉今天的人将被明天忘掉。","生活永远不像我们想的那样好，但也不会像我们想像的那样糟。","人生的价值，并不是用时间，而是用深度去衡量的。","一个人追求的目标越高，他的才力就发展得越快，对社会就越有益。","劳动一日，可得一夜的安眠；勤劳一生，可得幸福的长眠。","世界上最快乐的事，莫过于为理想而奋斗。","我要扼住命运的咽喉，它妄想使我屈服，这绝对办不到。生活是这样美好，活他一千辈子吧！ ","立志是事业的大门，工作是登门入室的的旅途。","发明家全靠一股了不起的信心支持，才有勇气在不可知的天地中前进。 ","把语言化为行动，比把行动化为语言困难得多。","耐心和恒心总会得到报酬的。","出淤泥而不染，濯清涟而不妖。","走自己的路，让别人说去！ ","立志是事业的大门，工作是登堂入室的旅程。","吾爱吾师，吾更爱真理。","给我一个支点，我可以撬起地球。 ","如果不想在世界上虚度一生，那就要学习一辈子。","书是人类进步的阶梯。","要成就一件大事业，必须从小事做起。","不想当将军的士兵，不是好士兵。","知识就是力量。","如果错过太阳时你流了泪，那么你也要错过群星。","良好的开端是成功的一半。","只有在那崎岖的小路上不畏艰险奋勇攀登的人，才有希望达到光辉的顶点。","要散布阳光到别人心里，先得自己心里有阳光。","美是到处都有的，对于我们的眼睛，不是缺少美，而是缺少发现。 ","你若要喜爱你自己的价值，你就得给世界创造价值。","受苦的人，没有悲观的权利。","一个人的价值，应该看他贡献什么，而不应当看他取得什么。","上天赋予的生命，就是要为人类的繁荣和平和幸福而奉献。","如果有一天，我能够对我们的公共利益有所贡献，我就会认为自己是世界上最幸福的人了。","认识了生活的全部意义的人，才不会随便死去，哪怕只有一点机会，就不会放弃生活。 ","忍耐和坚持虽是痛苦的事情，但却能渐渐地为你带来好处。","每一种恩惠都有一枚倒钩，它将钩住吞食那份恩惠的嘴巴，施恩者想把他拖到哪里就得到那里。","让我们享受人生的滋味吧，如果我们感受得越多，我们就会生活得越长久。 ","人只有献身于社会，才能找出那短暂而有风险的生命的意义。","思想家是主动的，梦幻家是被动的。","清晨的阳光不算温暖，瞬息的安逸不算幸福。","如果幸福在于肉体的快感，那么就应当说，牛找到草料吃的时候是幸福的。","享受着爱和荣誉的人，才会感到生存的乐趣。 ","荣誉是什么?就是别人的爱，希望为别人谋利而获得人们夸奖。","被人爱和爱别人是同样的幸福，而且一旦得到它，就够受用一辈子。","谁要在世界上遇到过一次友爱的心，体会过肝胆相照的境界，就是尝到了天上人间的欢乐。","精神的沟通用不着语言，只要是两颗充满着爱的心就行了。","最好的朋友是那种不喜欢多说，能与你默默相对而又息息息相通的人。","朋友看朋友是透明的;他们彼此交换生命。","社会犹如一条船，每个人都要有掌舵的准备。","路再长也有终点，夜再黑也有尽头。","人类所有的力量，只是耐心加上时间的混合，所谓强者，是既有意志，又能等待时机。 ","我们要消除这个暗礁，就必须等待时间、机会和有利条件。","真正的幸福只有当你真实地认识到人生的价值时，才能体会到。","一无所有的人是有福的，因为他们将获得一切! ","当你幸福的时候，切勿丧失使你成为幸福的德行。","生活的苦难压不垮我。我心中的欢乐不是我自己的，我把欢乐注进音乐，为的是让全世界感到欢乐。","时间是一个伟大的作者，它会给每个人写出完美的结局来。","从不浪费时间的人，没有工夫抱怨时间不够。 ","每一个人都嘲笑陈旧的时尚，却虔诚地追求新的时尚。","不是锤的打击，而是水的载歌载舞才形成了美丽的鹅卵石。","一个能思想的人，才真是一个力量无边的人。","他看到风向对他不利，就知道瞎忙也是白搭，唯一的办法是坐下来等待。","人类是唯一会脸红的动物，或是唯一该脸红的动物。","时间是世界上一切成就的土壤。时间给空想者痛苦，给创造者幸福。","治学有三大原则：广见闻，多阅读，勤实验。","勇于求知的人决不至于空闲无事。","没有感恩就没有真正的美德。","不要心平气和，不要容你自己昏睡!趁你还年轻，强壮、灵活，要永不疲倦地做好事。","沉沉的黑夜都是白天的前奏。","推动你的事业，不要让你的事业推动你。","壮志与热情是伟业的辅冀。","一个人如同一只钟表，是以他的行动来确定其价值。 ","信仰是伟大的情感，一种创造力量。","智慧、勤劳和天才，高于显贵和富有。","为什么只看到你兄弟身上有刺，而不是你眼中有梁木呢？ ","忘掉今天的人将被明天忘掉。","人的全部本领无非是耐心和时间的混合物。","创造者才是真正的享受者。","既然我已经踏上这条道路，那么，任何东西都不应妨碍我沿着这条路走下去。","坚持意志伟大的事业需要始终不渝的精神。","节制使快乐增加并使享受加强。","懒人无法享受休息之乐。","时间是我的财产，我的田亩是时间。","求学如值树，春天开花，秋天结果。","生活中唯一乐趣就是忘却。","暂时的是现实，永生的是理想。","人的心灵是有翅膀的，会在梦中飞翔。"
                     };

int ran(int x) {
	srand(time(NULL) + x * x);
	return rand();
}

void say_sentence(int y) {
	int n = ran(222 + y) % numn, v = ran(333 + y) % numv, aj = ran(444 + y) % numadj, av = ran(555 + y) % numadv, aj2 = ran(888 + y) % numadj, n2 = ran(999 + y) % numn, n3 = ran(1444 + y) % numn, alike = ran(666 + y) % numl;
	int ic = ran(111 + y) % 7, c1 = ran(777 + y) % numcon, ic2 = ran(1111 + y) % 7, il = ran(1222 + y) % 2, in = ran(1333 + y) % 2, c2 = ran(1444 + y) % 3;
	if(ic % 3 == 0) {
		cout << con_j[c1] << ",";
	}
	cout << adj[aj] << "的" << nouns[n] << adv[av] << "地";
	if(il) {
		cout << like[alike] << adj[aj2] << "的" << nouns[n2];
	}
	cout << verbs[v];
	if(ic2 % 2 == 0) {
		cout << connect[c2];
	}
	if(in) {
		cout << nouns[n3];
	}
	cout << ".";
	return;
}

void question(int y) {
	int n = ran(2111 + y) % numn, v = ran(2222 + y) % numv, aj = ran(2333 + y) % numadj, av = ran(2444 + y) % numadv, n2 = ran(3222 + y) % numn, aj2 = ran(3333 + y) % numadj, v2 = ran(3555 + y) % numv, alike = ran(2555 + y) % numl;
	int c = ran(2666 + y) % 3, qq = ran(2777 + y) % 3, num = ran(2888 + y) % 2, ob1 = ran(2999 + y) % 4, ob2 = ran(3111 + y) % 3, il = ran(3444 + y) % 2;
	if(num) {
		cout << ques[qq];
	} 
	else {
		cout << obq[ob1];
	}
	cout << adj[aj] << "的" << nouns[n] << adv[av] << "地", verbs[v2];
	if(il) {
		cout << like[alike] << adj[aj2] << "的" << nouns[n2];
	}
	if(!num) {
		cout << "不";
	}
	cout << verbs[v];
	if(num) {
		cout << connect[c];
	} 
	else {
		cout << obend[ob2];
	}
	cout << "?";
	return;
}

void gts(int y) {
	int n = ran(4111 + y) % numn, v = ran(4222 + y) % numv, aj = ran(4333 + y) % numadj, av = ran(4444 + y) % numadv, aj2 = ran(7333 + y) % numadj, alike = ran(7555 + y) % numl, n2 = ran(7999 + y) % numn;
	int gg = ran(4555 + y) % 3, ggg = ran(4666 + y) % 3, ig = ran(4777 + y) % 2, il = ran(4888 + y) % 2;
	cout << adj[aj] << "的" << nouns[n];
	if(ig){
		cout << gt[gg];
	} 
	cout << adv[av] << "地" << verbs[v];
	if(il){
		cout << like[alike] << adj[aj2] << "的" << nouns[n2];
	}
	cout << gtback[ggg] << "!";
	return;
}

void paragraph(int y) {
	cout << "    ";
	y += ran(j + 5111) % 15 + 15;
	for(int i = 1; i <= y; i++) {
		int u = ran(i + 5222 + j) % 4, uu = ran(i + 5444 + y) % 10, af = ran(i + 5777+ y) % numfam;
		if(u) {
			say_sentence(i + 5333 + y);
		} 
		else {
			if(uu <= 2) {
				gts(i + 5555 + y);
			} 
			else if(uu <= 6) {
				question(i + 5666 + y * y);
			} 
			else {
				cout << famous[af];
			}
		}
	}
	cout << endl;
	return;
}

int main() {
	freopen("文章.txt","w",stdout);
	int paras = ran(6666) % 15 + 5;
	for(j = 1; j <= paras; j++) {
		paragraph(j + 1);
	}
	return 0;
}