rt。 代码:
#include<bits/stdc++.h>
#define dd double
#define ld long double
#define ll long long
#define uint unsigned int
#define ull unsigned long long
#define N 1000010
#define M 600010
using namespace std;
const int INF=0x3f3f3f3f;
template<typename T> inline void read(T &x) {
x=0; int f=1;
char c=getchar();
for(;!isdigit(c);c=getchar()) if(c == '-') f=-f;
for(;isdigit(c);c=getchar()) x=x*10+c-'0';
x*=f;
}
int n,m,k;
int fa[M],deep[M],top=0;
pair<int,int> sta[M];
struct bingchaji{
int find(int a){
return a==fa[a]?a:find(fa[a]);
}
bool belong_to_the_same(int a,int b){
int faa=find(a),fab=find(b);
return faa==fab;
}
bool merge(int a,int b){
int faa=find(a),fab=find(b);
if(faa==fab) return 0;
if(deep[faa]>deep[fab]) swap(faa,fab);
fa[faa]=fab;sta[++top]=make_pair(faa,deep[fab]);
if(deep[faa]==deep[fab]) deep[fab]++;
return 1;
}
void chushihua(int n){
for(int i=1;i<=n;i++) fa[i]=i,deep[i]=0;top=0;
}
void chexiao(int k){
for(int i=1;i<=k;i++){
int lastdian=sta[top].first,lastdeep=sta[top].second;
deep[fa[lastdian]]=lastdeep;fa[lastdian]=lastdian;top--;
}
}
};
bingchaji bcj;
struct edge{
int from,to;
edge(){}
edge(int from,int to) : from(from),to(to) {}
};
struct node{
int l,r;
node(){l=r=0;}
};
vector<edge> bian[N<<2];
node p[N<<2];
int tot=0,root=0;
bool ans[M];
int new_node(){
tot++;p[tot].l=p[tot].r=0;return tot;
}
void change(int &k,int l,int r,int z,int y,int u,int v){
if(k==0) k=new_node();
if(l==z&&r==y){
bian[k].push_back(edge(u,v));return;
}
int mid=(l+r)>>1;
if(y<=mid) change(p[k].l,l,mid,z,y,u,v);
else if(z>mid) change(p[k].r,mid+1,r,z,y,u,v);
else change(p[k].l,l,mid,z,mid,u,v),change(p[k].r,mid+1,r,mid+1,y,u,v);
}
void solve(int &k,int l,int r,bool op){
if(l>r) return;
if(!k) k=new_node();
int mid=(l+r)>>1,cnt=0;
for(int j=0;j<bian[k].size()&&op;j++){
edge nowbian=bian[k][j];
if(bcj.belong_to_the_same(nowbian.from,nowbian.to)){
op=0;break;
}
bcj.merge(nowbian.from,nowbian.to+n);cnt++;
bcj.merge(nowbian.to,nowbian.from+n);cnt++;
}
if(l==r){ans[l]=op;bcj.chexiao(cnt);return;}
if(op){solve(p[k].l,l,mid,op);solve(p[k].r,mid+1,r,op);}
bcj.chexiao(cnt);
}
int main(){
read(n);read(m);read(k);
for(int i=1;i<=m;i++){
int x,y,l,r;read(x);read(y);read(l);read(r);l++;
if(l>r) continue;
change(root,1,k,l,r,x,y);
}
bcj.chushihua(n<<1);
solve(root,1,k,1);
for(int i=1;i<=k;i++) if(ans[i]) printf("Yes\n");else printf("No\n");
return 0;
}