代码如下:
(思路就是转化成分钟再减再转化回来)
#include <cstdio>
#include <iostream>
#include <vector>
#include <sstream>
#include <string>
#include <map>
#include <set>
#include <list>
using namespace std;
int main() {
int a, b, c ,d;
cin >> a >> b >> c >> d;
int ab = a * 60 + b;
int cd = b * 60 + c;
long long time = cd - ab;
int e, f;
if (time > 60) {
e++;
time -= 60;
}
cout << e << " " << time << endl;
return 0;
}