样例过了，下载的测试数据也过了QwQ

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
	int n,k,sum1=0,sum2=0,a1=0,a2=0;
	double ans1,ans2;
	cin>>n>>k;
	for(int i=1;i<=n;i++)
	{
		if(i%k==0)
		{
			sum1+=i;
			a1++;
		}
		else
		{
			sum2+=i;
			a2++;
		}
	}
	ans1=1.0*sum1/a1;
	ans2=1.0*sum2/a2;
	printf("%.1llf %.1llf\n",ans1,ans2);
	return 0;
}