已知 a3+b3+3ab=1a^3+b^3+3ab=1a3+b3+3ab=1，求 a,ba,ba,b 之间的的数量关系。
答案： {a=1−b, unconditionallya=−1, b=−1\left\{\begin{matrix}\\a=1-b\text{, }&\text{unconditionally}\\a=-1\text{, }&b=-1\end{matrix}\right.⎩⎨⎧a=1−b, a=−1, unconditionallyb=−1
{b=1−a, unconditionallyb=−1, a=−1\left\{\begin{matrix}\\b=1-a\text{, }&\text{unconditionally}\\b=-1\text{, }&a=-1\end{matrix}\right.⎩⎨⎧b=1−a, b=−1, unconditionallya=−1
求解题过程。
