这是一种模拟的写法

#include<iostream>
#include<cstring>
#include<cmath>
using namespace std;
int ans[12345],x;
bool f,r;
char ai[12345];
void d() {

	while (scanf("%s", ai)!=EOF) {
		int v=strlen(ai);
		if(v==0) return ;
		r=1;
		if(v==2) return ;
		int i=1;
		string temp;
		for(; ai[i]!=','; ++i) {
			temp=temp+ai[i];
		}	
		i++;
		int t=1;
		for(; i<v-1; ++i) {
			if(ai[i]=='L') t*=2;
			else t=t*2+1;
		}
		x=max(x,t);
		int num=0;
		int k=temp.size();
		for(int j=0; j<k; ++j) {
			num+=int(temp[j]-'0')*pow(10,(k-j-1));
		}
		if(ans[t]) {
			f=1;
			return ;
		}
		ans[t]=num;
	}r=0;
}
int main() {
	while(1) {
		memset(ans,0,sizeof(ans));
		f=0;
		x=0;
		r=0;
		d();
		if(r==0) return 0;
		if(f==1) {
			cout<<"not complete"<<endl;
			continue;
		}
		if(ans[1]) cout<<ans[1]<<" ";
		for(int i=2; i<=x; ++i) {
			if(i%2) {
				int j=(i-1)/2;
				if(ans[j]) if(ans[i]==0) continue;
					else
						cout<<ans[i]<<" ";
				else {
					if(!ans[i]) continue;
					cout<<"not complete"<<endl;
					break;
				}
			} else {
				int j=i/2;
				if(ans[j]) if(!ans[i]) continue;
					else
						cout<<ans[i]<<" ";
				else {
					if(!ans[i]) continue;
					cout<<"not complete"<<endl;
					break;
				}
			}
		}
	}
}