∑i=1n(μ(i)2)=∑i=1∣n∣∣(ni2∣μ(i))\sum_{i=1}^{n}(\mu(i)^2)=\sum_{i=1}^{|\sqrt{n}|}|(\frac{n}{i^2}|\mu(i))∑i=1n(μ(i)2)=∑i=1∣n∣∣(i2n∣μ(i))
