bi=min 1<=j<=i∣ai−aj∣,i>=1b_{i}=min\;1<=j<=i|a_{i}-a_{j}|,i>=1bi=min1<=j<=i∣ai−aj∣,i>=1
因该为：
bi=min 1<=j<i∣ai−aj∣,i>1b_{i}=min\;1<=j<i|a_{i}-a_{j}|,i>1bi=min1<=j<i∣ai−aj∣,i>1
