题解
查看原帖
题解
5996
翰浩楼主2015/2/11 10:30
var
  a,b,i,j,sum:longint;
  x:ansistring;
  b1:string;
begin
  read(a,b);
  str(b,b1);
  for i:=1 to a do begin
    str(i,x);
    for j:=1 to length(x) do
      if x[j]=b1 then sum:=sum+1;
  end;
  write(sum);
end.

2015/2/11 10:30
加载中...