代码：

#include<bits/stdc++.h>
using namespace std;
int main() 
{
    int n,m,a,b;
    cin>>n>>m>>a>>b;
    int left=0;
    int right=min(n/a,m/b)+min(n/b,m/a);
    int ans=0;
    while(left<=right) 
    {
        int mid=left+(right-left)/2; 
        bool ch1=a*mid<=n&&b*mid<=m;
        bool ch2=b*mid<=n&&a*mid<=m;
        if(ch1||ch2) 
        {
            ans=mid;
            left=mid+1;
        } 
        else 
        {
            right=mid-1;
        }
    }
    cout<<ans<<endl;
    return 0;
}

结果五彩斑斓

求条，悬2关