Code1
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, r;
cin >> n >> r;
cout << int(pow(n, r)) - n;
return 0;
}
Code2
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, r, ans = 1;
cin >> n >> r;
for (int i = 0; i < r; i++) {
ans *= n;
}
cout << ans - n;
return 0;
}
Code3
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, r;
long long ans = 1;
cin >> n >> r;
for (int i = 0; i < r; i++) {
ans *= n;
}
cout << ans - n;
return 0;
}
Code4
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, r;
cin >> n >> r;
cout << int(pow(r, n)) - 2;
return 0;
}
Code5
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, r;
cin >> n >> r;
cout << int(pow(r, n)) - r;
return 0;
}
Help
20 分求调,帮助的必关
验证码:g2zz